JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
\(5\, moles\) of an ideal gas at \(100\, K\) are allowed to undergo reversible compression till its temperature becomes \(200\, K\). If \(C_v = 28 \, J\,K^{-1}\, mol^{-1}\) , calculate \(\Delta U\) and \(\Delta pV\) for this process. \((R = 8.0\, J\, K^{-1}\, mol^{-1})\)
- A \(\Delta U = 2.8\,k\,J ; \Delta (pV) = 0.8\,k\,J\)
- B \(\Delta U = 14\,k\,J ; \Delta (pV) = 4\,k\,J\)
- C \(\Delta U = 14\,k\,J ; \Delta (pV) = 18\,k\,J\)
- D \(\Delta U = 14\,k\,J ; \Delta (pV) = 0.8\,J\)
Answer & Solution
Correct Answer
(B) \(\Delta U = 14\,k\,J ; \Delta (pV) = 4\,k\,J\)
Step-by-step Solution
Detailed explanation
\(\Delta U = n{C_v}m \times \Delta T\) \( = 5 \times 28 \times 100 = 14\,k\,J\) \(\Delta PV = nR\Delta T\) \( = 5 \times 8 \times 100\) \( = 4\,k\,J\)
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