JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of vessel is \(5\,cm\) and its rotational speed is \(2\) rotations per second, then the difference in the heights between the centre and the sides, in \(cm,\) will be
- A \(2.0\)
- B \(0.1\)
- C \(0.4\)
- D \(1.2\)
Answer & Solution
Correct Answer
(A) \(2.0\)
Step-by-step Solution
Detailed explanation
\(y = \frac{{{w^2}{x^2}}}{{2g}} = \frac{{{{\left( {2 \times 2\pi } \right)}^2} \times {{\left( {0.05} \right)}^2}}}{{2g}}\) \( = 25 \times 8 \times {10^{ - 4}}\) \( = 2\,cm\,\,\,\,\)
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