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JEE Mains · Chemistry · STD 11 - 2. structure of atom

The Bohr radius of a hydrogen like species is \(70.53\) pm. The species and the stationary state \((n)\) are respectively (Given : Hydrogen atom Bohr radius is \(52.9\) pm)

  1. A \(\text{Li}^{2+}, 3\)
  2. B \(\text{He}^+, 3\)
  3. C \(\text{He}^+, 2\)
  4. D \(\text{Li}^{2+}, 2\)
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Answer & Solution

Correct Answer

(D) \(\text{Li}^{2+}, 2\)

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Detailed explanation

The radius of the \(n\)-th Bohr orbit for a hydrogen-like species is given by the formula: \(r_n = a_0 \dfrac{n^2}{Z}\) where \(a_0\) is the Bohr radius of the hydrogen atom (\(52.9\) pm), \(n\) is the principal quantum number, and \(Z\) is the atomic number. Given…
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