JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A body of mass \({M}\) moving at speed \({V}_{0}\) collides elastically with a mass \('m'\) at rest. After the collision, the two masses move at angles \(\theta_{1}\) and \(\theta_{2}\) with respect to the initial direction of motion of the body of mass \({M}\). The largest possible value of the ratio \({M} / {m}\), for which the angles \(\theta_{1}\) and \(\theta_{2}\) will be equal, is :
- A \(4\)
- B \(1\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
given \(\theta_{1}=\theta_{2}=\theta\) from momentum conservation in \(x\)-direction \(M V_{0}=M V_{1} \cos \theta+m V_{2} \cos \theta\) in \({y}\)-direction \(0={MV}_{1} \sin \theta-{m} {V}_{2} \sin \theta\) Solving above equations…
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