JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
When a \(60\,W\) electric heater is immersed in a gas for \(100\,s\) in a constant volume container with adiabatic walls, the temperature of the gas rises by \(5^{\circ}\,C\). The heat capacity of the given gas is \(.........\,JK ^{-1}\) (Nearest integer)
- A \(1100\)
- B \(1200\)
- C \(1000\)
- D \(1600\)
Answer & Solution
Correct Answer
(B) \(1200\)
Step-by-step Solution
Detailed explanation
Power of heater \(=60\,W\) \(=60\,J / sec\) Total energy emitted \(=60 \times 100=6000\,J\) Heat capacity \(\times\) temp difference \(=6000\) Heat capacity \(=\frac{6000}{5}=1200\,JK ^{-1}\)
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