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JEE Mains · Chemistry · STD 11 - 2. structure of atom

The energy of first (lowest) Balmer line of H atom is x J. The energy (in J) of second Balmer line of H atom is:

  1. A \(x^{2}\)
  2. B \(\frac{x}{1.35}\)
  3. C 2x
  4. D 1.35x
Verified Solution

Answer & Solution

Correct Answer

(D) 1.35x

Step-by-step Solution

Detailed explanation

Transition of first Balmer line \(n_1=2 ; n_2=3\) \(\Delta E=x=13.6(1)^2\left[\frac{1}{2^2}-\frac{1}{3^2}\right] \quad\ldots(i)\) Transition of \(2^{\text {nd }}\) Balmer line \(n_1=2 ; n_2=4\) \(\Delta E=13.6(1)^2\left[\frac{1}{2^2}-\frac{1}{4^2}\right]\quad\ldots(ii)\) Divide…
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