JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(1\,g\) of a carbonate \(\left( M _2 CO _3\right)\) on treatment with excess \(HCl\) produces \(0.01 mol\) of \(CO _2\) The molar mass of \(M _2 CO _3\) is \(..........\,g\,mol ^{-1}\). (Nearest integer)
- A \(200\)
- B \(300\)
- C \(50\)
- D \(100\)
Answer & Solution
Correct Answer
(D) \(100\)
Step-by-step Solution
Detailed explanation
\(\underset{1\,gm }{ M _2 CO _3}+\underset{\text { Excess }}{2 HCl } \rightarrow \underset{0.02 \text { mole }}{2 MCl }+ H _2 O +\underset{0.01 \text { mole }}{ CO _2}\) From principle of atomic conservation of carbon atom, Mole of \(M _2 CO _3 \times 1=\) Mole of…
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