JEE Mains · Physics · STD 12 - 13. Nuclei
Two radioactive substances \(A\) and \(B\) have decay constants \(5\lambda \) and \(\lambda \) respectively. At \(t = 0\), a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become \((\frac {1}{e})^2\) will be
- A \(1/\lambda \)
- B \(1/4\lambda \)
- C \(2/\lambda \)
- D \(1/2\lambda \)
Answer & Solution
Correct Answer
(D) \(1/2\lambda \)
Step-by-step Solution
Detailed explanation
\(\frac{1}{{{e^2}}} = {e^{\lambda t - 5\lambda t}}\) \(t\, = \,\frac{1}{{2\lambda }}\)
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