ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

Oxidation state of Fe(Iron) in complex formed in Brown ring test.

  1. A 2
  2. B 4
  3. C 5
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(D) 1

Step-by-step Solution

Detailed explanation

Complex formed during brown ring test is \(\left[Fe\left(H_2 O\right)_5 NO\right] SO_4 .\) NO is present as \(NO ^{+}\)here. \(\begin{array}{l}x+5 \times 0+1=+2 \\x=+1\end{array}\) Oxidation state of Fe is +1
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app