JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Oxidation state of Fe(Iron) in complex formed in Brown ring test.
- A 2
- B 4
- C 5
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
Complex formed during brown ring test is \(\left[Fe\left(H_2 O\right)_5 NO\right] SO_4 .\) NO is present as \(NO ^{+}\)here. \(\begin{array}{l}x+5 \times 0+1=+2 \\x=+1\end{array}\) Oxidation state of Fe is +1
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