JEE Mains · Chemistry · STD 11 - 2. structure of atom
Based on the equation \(\Delta E = - 2.0 \times {10^{ - 18}}\,J\left( {\frac{1}{{n_2^2}} - \frac{1}{{n_1^2}}} \right)\) the wavelength of the light that must be absorbed to excite hydrogen electron from level \(n\, = 1\) to level \(n\, = 2\) will be: \((h\, = 6.625\times10^{-34}\, J\,s,\, C\, = 3\times10^8\, m\,s^{-1})\)
- A \(1.325\times10^{-7}\, m\)
- B \(1.325\times10^{-10}\, m\)
- C \(2.650\times10^{-7}\, m\)
- D \(5.300\times10^{-10}\, m\)
Answer & Solution
Correct Answer
(A) \(1.325\times10^{-7}\, m\)
Step-by-step Solution
Detailed explanation
\(\Delta E = - 2.0 \times {10^{ - 18}} \times \left( {\frac{1}{{{2^2}}} - \frac{1}{{{1^2}}}} \right)\) \( = - 2.0 \times {10^{ - 18}} \times \frac{{ - 3}}{4}\) \( = 1.5 \times {10^{ - 18}}\) \(\Delta E = \frac{{hc}}{\lambda }\)…
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