JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In the given figure, each diode has a forward bias resistance of \(30\, \Omega\) and infinite resistance in reverse bias. The current \({I}_{1}\) will be \(....\,A\)
- A \(3.75\)
- B \(2.35\)
- C \(2\)
- D \(2.73\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
As per diagram, Diode \({D}_{1} \& {D}_{2}\) are in forward bias i.e. \({R}=30 \,\Omega\) whereas diode \({D}_{3}\) is in reverse bias i.e. \({R}=\) infinite \(\Rightarrow\) Equivalent circuit will be Applying \(KVL\) starting from point \(A\)…
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