JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2021
- Hard
- Numerical
In the given figure, each diode has a forward bias resistance of \(30\, \Omega\) and infinite resistance in reverse bias. The current \({I}_{1}\) will be \(....\,A\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
As per diagram,
Diode \({D}_{1} \& {D}_{2}\) are in forward bias i.e. \({R}=30 \,\Omega\)
whereas diode \({D}_{3}\) is in reverse bias i.e. \({R}=\) infinite
\(\Rightarrow\) Equivalent circuit will be
Applying \(KVL\) starting from point \(A\)
\(-\left(\frac{{I}_{1}}{2}\right) \times 30-\left(\frac{{I}_{1}}{2}\right) \times 130-{I}_{1} \times 20+200=0\)
\(\Rightarrow-100 {I}_{1}+200=0\)
\({I}_{1}=2\)
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