JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Match List\(-I\) with List\(-II\).
| List\(-I\) | List\(-II\) |
| \(A\) \(16\,g \text { of } CH _{4( g )}\) | \(I\) Weighs \(28\,g\) |
| \(B\) \(1\,g \text { of } H _{2( g )}\) | \(II\) \(60.2 \times 10^{23}\) electrons |
| \(C\) \(1\,mole \text { of } N _{2( g )}\) | \(III\) Weighs \(32\,g\) |
| \(D\) \(0.5\,mol\) of \(SO _{2( g )}\) | \(IV\) Occupies \(11.4\,L\) volume at STP |
- A \(A-I, B-III, C-II, D-IV\)
- B \(A-II, B-III, C-IV, D-I\)
- C \(A-II, B-IV, C-III, D-I\)
- D \(A-II, B-IV, C-I, D-III\)
Answer & Solution
Correct Answer
(D) \(A-II, B-IV, C-I, D-III\)
Step-by-step Solution
Detailed explanation
\(16\,g\,CH _4=1\) mole \(CH _4\) contains \(10 \times 6.02 \times 10^{23}\) electrons \(=60.2 \times 10^{23}\) \(1\,g\,H _2=0.5\) mole \(H _2\) gas occupy \(11.35\) litre volume at STP \(1 \text { mole of } N _2=28\,g\) \(0.5 \text { mole of } SO _2=32\,g\)
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