JEE Mains · Chemistry · STD 11 - 7. Redox reactions
One mole of \(Cl_{2}\) (g) was passed into 2 L of cold 2M KOH solution. After the reaction, the concentrations of \(Cl^{-}\), \(ClO^{-}\) and \(OH^{-}\) are respectively (assume volume remains constant):
- A 0.75 M, 0.75 M, 1 M
- B 0.5 M, 0.5 M, 0.5 M
- C 0.5 M, 0.5 M, 1 M
- D 1 M, 1 M, 1 M
Answer & Solution
Correct Answer
(C) 0.5 M, 0.5 M, 1 M
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}Cl _2+2 KOH \rightarrow KCl + KClO + H _2 O \\ t =0 \quad 1 \text { mole } \quad 4 \text { mole } \\ t _{ f } \quad 0 \quad 2 \text { mole } \quad 1 \text { mole } 1 \text { mole }\end{array}\) \(\left[ OH ^{-}\right]=1 M\)…
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