JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
A gas undergoes change from state \(A\) to state \(B\). In this process, the heat absorbed and work done by the gas is \(5\, J\) and \(8\, J\), respectively. Now gas is brought back to \(A\) by another process during which \(3\, J\) of heat is evolved. In this reverse process of \(B\) to \(A\)
- A \(10\, J\) of the work will be done by the gas
- B \(6\, J\) of the work will be done by the gas
- C \(10\, J\) of the work will be done by the surrounding on gas
- D \(6\, J\) of the work will be done by the surrounding on gas.
Answer & Solution
Correct Answer
(D) \(6\, J\) of the work will be done by the surrounding on gas.
Step-by-step Solution
Detailed explanation
\(\Delta {U_{AB}} = q + w = + 5 + ( - 8) = - 3\) \(q = - 3,\,\Delta {U_{BA}} = + 3\) \(\Delta {U_{BA}} = q + w\) \( \Rightarrow 3 = - 3 + w \Rightarrow w = + 6\) (work done on the system)
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