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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

The correct order of the number of unpaired electrons in the given complexes is \(A.\) \(\left[ Fe ( CN )_6\right]^{3-}\);\(B.\) \(\left[ FeF _6\right]^{3-}\); \(C.\) \(\left[ CoF _6\right]^{3-}\); \(D.\) \(\left[ Cr (\text { oxalate })_3\right]^{3-}\); \(E.\) \(\left[ Ni ( CO )_4\right]\) Choose the correct answer from the options given below:

  1. A \(A < E < D < C < B\)
  2. B \(E < A < D < C < B\)
  3. C \(E < A < B < D < C\)
  4. D \(A < E < C < B < D\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(E < A < D < C < B\)

Step-by-step Solution

Detailed explanation

\(A\). \(\left[ Fe ( CN )_6\right]^{3-} n =1\) \(B\). \(\left[ FeF _6\right]^{3-} n =5\) \(C\). \(\left[ CoF _6\right]^{3-} n =4\) \(D\). \(\left.[\text { Cr(oxalate })_3\right]^{3-} n =3\) \(E\). \(\left[ Ni ( CO )_4\right] n =0\)
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