JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
One Faraday of electricity liberates \(\mathrm{x} \times 10^{-1}\) gram atom of copper from copper sulphate, \(\mathrm{x}\) is _______.
- A \(4\)
- B \(5\)
- C \(6\)
- D \(7\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}\) \(2 \text { Faraday } \rightarrow 1 \mathrm{~mol} \mathrm{Cu}\) \(1 \text { Faraday } \rightarrow 0.5 \mathrm{~mol} \mathrm{Cu} \text { deposit }\) \(0.5 \mathrm{~mol}=0.5 \mathrm{~g} \text { atom }=5 \times 10^{-1}\)…
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