JEE Mains · Physics · STD 12 -7. Alternating current
In the given circuit, rms value of current \(\left( I _{ rms }\right)\) through the resistor \(R\) is :\(..........\,A\)
- A \(2\)
- B \(\frac{1}{2}\)
- C \(20\)
- D \(2 \sqrt{2}\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(z =\sqrt{100^2+(200-100)^2}\) \(=100 \sqrt{2}\,\Omega\) \(i _{ rms }=\frac{ V _{ rms }}{ z }=\frac{200 \sqrt{2}}{100 \sqrt{2}}\) \(=2\,A\)
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