JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The molarity of \(\mathrm{HNO}_{3}\) in a sample which has density \(1.4 \;\mathrm{g} / \mathrm{mL}\) and mass percentage of \(63 \%\) is ______ \(\mathrm{M}\) થશે. (Molecular Weight of \(\mathrm{HNO}_{3}=63\) )
- A \(22\)
- B \(19\)
- C \(17\)
- D \(14\)
Answer & Solution
Correct Answer
(D) \(14\)
Step-by-step Solution
Detailed explanation
\(100\, \mathrm{gm}\) soln \(\rightarrow 63\, \mathrm{gm} \mathrm{HNO}_{3}\) \(\frac{100}{1.4} \mathrm{mL} \rightarrow 1\) mole \(\mathrm{HNO}_{3}\) Molarity \(=\frac{1}{\frac{100}{1.4} \times \frac{1}{1000}}=14 \;\mathrm{M}\)
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