JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2014
- Hard
- MCQ
A particle is moving in a circular path of radius \(a,\) with a constant velocity \(v\) as shown in the figure.The centre of circle is marked by \('C'\). The angular momentum from the origin \(O\) can be written as

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(va\,\, ( 1 + cos\,2\theta )\)
Step-by-step Solution
Detailed explanation
\((v \cos \theta) \times 2\) turns
\(2 \cos v a-1=\cos 2 w\)
\(2 \mathrm{rv} \cos ^{2} \mathrm{v}\)
va \((1+\cos 2 \theta)\)
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