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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2014
  • Hard
  • MCQ

A particle is moving in a circular path of radius \(a,\) with a constant velocity \(v\) as shown in the figure.The centre of circle is marked by \('C'\). The angular momentum from the origin \(O\) can be written as

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Answer & Solution

Correct Answer

(A) \(va\,\, ( 1 + cos\,2\theta )\)

Step-by-step Solution

Detailed explanation

\((v \cos \theta) \times 2\) turns

\(2 \cos v a-1=\cos 2 w\)

\(2 \mathrm{rv} \cos ^{2} \mathrm{v}\)

va \((1+\cos 2 \theta)\)

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