JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Match List\(-I\) with List\(-II :\)
| List\(-I\) (Species) | List\(-II\) (Hybrid Orbitals) |
| \((a)\) \(\mathrm{SF}_{4}\) | \((i)\) \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) |
| \((b)\) \(\mathrm{IF}_{5}\) | \((ii)\) \(\mathrm{d}^{2} \mathrm{sp}^{3}\) |
| \((c)\) \(\mathrm{NO}_{2}^{+}\) | \((iii)\) \(\mathrm{sp}^{3} \mathrm{~d}\) |
| \((d)\) \(\mathrm{NH}_{4}^{+}\) | \((iv)\) \(\mathrm{sp}^{3}\) |
| \((v)\) \(\mathrm{sp}\) |
- A \((a)-(i), (b)-(ii), (c)-(v)\) and \((d)-(iii)\)
- B \((a)-(ii), (b)-(i), (c)-(iv)\) and \((d)-(v)\)
- C \((a)-(iv), (b)-(iii), (c)-(ii)\) and \((d)-(v)\)
- D \((a)-(iii), (b)-(i), (c)-(v)\) and \((d)-(iv)\)
Answer & Solution
Correct Answer
(D) \((a)-(iii), (b)-(i), (c)-(v)\) and \((d)-(iv)\)
Step-by-step Solution
Detailed explanation
\((a)\) \(\mathrm{SF}_{4}-\mathrm{sp}^{3} \mathrm{~d}\) hybridisation \((b)\) \(IF_{5}-\mathrm{sp}^{3} \mathrm{~d}^{2}\) hybridisation \((c)\) \(\mathrm{NO}_{2}^{+}-\mathrm{sp}\) hybridisation \((d)\) \(\mathrm{NH}_{4}^{+}-\mathrm{sp}^{3}\) hybridisation
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