JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2024
- Hard
- Numerical
When a dc voltage of \(100 \mathrm{~V}\) is applied to an inductor, a dc current of \(5 \mathrm{~A}\) flows through \(1\) . When an ac voltage of \(200 \mathrm{~V}\) peak value is connected to inductor, its inductive reactance is found to be \(20 \sqrt{3} \Omega\). The power dissipated in the circuit is _______\(W\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(250\)
Step-by-step Solution
Detailed explanation
For \(DC\) voltage
\(\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}}=\frac{100}{5}=20 \Omega\)
for \(AC\) voltage
\(\mathrm{X}_{\mathrm{L}}=20 \sqrt{3} \Omega\)
\(\mathrm{R}=20 \Omega\)
\(\mathrm{Z}=\sqrt{\mathrm{X}_{\mathrm{L}}^2+\mathrm{R}^2}=\sqrt{3 \times 400+400}=40\)
Power \(-i_{\text {rms }}^2 R\)
\(=\left(\frac{\mathrm{V}_{\text {rms }}}{\mathrm{Z}}\right)^2 \times \mathrm{R}=\left(\frac{\frac{200}{\sqrt{2}}}{40}\right)^2 \times 20=250 \mathrm{~W}\)
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