JEE Mains · Physics · STD 11 - 4.2 friction
A car of \(800 \mathrm{~kg}\) is taking turn on a banked road of radius \(300 \mathrm{~m}\) and angle of banking \(30^{\circ}\). If coefficient of static friction is \(0.2\) then the maximum speed with which car can negotiate the turn safely which? \(\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2, \sqrt{3}=1.73\right)\)
- A \(70.4 \mathrm{~m} / \mathrm{s}\)
- B \(51.4 \mathrm{~m} / \mathrm{s}\)
- C \(264 \mathrm{~m} / \mathrm{s}\)
- D \(102.8 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(B) \(51.4 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{m}=800 \mathrm{~kg}\) \(\mathrm{r}=300 \mathrm{~m}\) \(\theta=30^{\circ}\) \(\mu_2=0.2\) \(\mathrm{~V}_{\max }=\sqrt{\operatorname{Rg}\left[\frac{\tan \theta+\mu}{1-\mu \tan \theta}\right]}\)…
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