JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
In the ground state of atomic \(Fe \,( Z =26)\) the spin-only magnetic moment is ...... \(\times 10^{-1} \,BM\). (Round off to the Nearest Integer). \([\) Given \(: \sqrt{3}=1.73, \sqrt{2}=1.41]\)
- A \(95\)
- B \(49\)
- C \(22\)
- D \(84\)
Answer & Solution
Correct Answer
(B) \(49\)
Step-by-step Solution
Detailed explanation
\(Fe \rightarrow[ Ar ] 4 s ^{2} 3 d ^{6}\) \(\uparrow \downarrow\) \(\uparrow\) \(\uparrow\) \(\uparrow\) \(\uparrow\) Number of unpaired \(e ^{-}=4\) \(\mu=\sqrt{4(4+2)} \,B.M.\) \(\mu=\sqrt{24}\, B.M\) \(\mu=4.89\, B.M\) \(\mu=48.9 \times 10^{-1}\, B.M\) Nearest integer value…
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