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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(\mathrm{K}_{\mathrm{n}}\) for \(\mathrm{CH}_3 \mathrm{COOH}\) is \(1.8 \times 10^{-3}\) and \(\mathrm{K}_{\mathrm{b}}\) for \(\mathrm{NH}_4 \mathrm{OH}\) is \(1.8 \times 10^{-5}\). The \(\mathrm{pH}\) of ammonium acetate solution will be _______.

  1. A \(5\)
  2. B \(7\)
  3. C \(8\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7\)

Step-by-step Solution

Detailed explanation

\(\mathrm{pH}=\frac{\mathrm{pK}_{\mathrm{w}}+\mathrm{pK}_{\mathrm{a}}-\mathrm{pK}_{\mathrm{b}}}{2}\) \(\mathrm{pK}_{\mathrm{a}}=\mathrm{pK}_{\mathrm{b}}\) \(\Rightarrow \mathrm{pH}=\frac{\mathrm{pK}_{\mathrm{W}}}{2}=7\)