JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
\(\mathrm{K}_{\mathrm{n}}\) for \(\mathrm{CH}_3 \mathrm{COOH}\) is \(1.8 \times 10^{-3}\) and \(\mathrm{K}_{\mathrm{b}}\) for \(\mathrm{NH}_4 \mathrm{OH}\) is \(1.8 \times 10^{-5}\). The \(\mathrm{pH}\) of ammonium acetate solution will be _______.
- A \(5\)
- B \(7\)
- C \(8\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(7\)
Step-by-step Solution
Detailed explanation
\(\mathrm{pH}=\frac{\mathrm{pK}_{\mathrm{w}}+\mathrm{pK}_{\mathrm{a}}-\mathrm{pK}_{\mathrm{b}}}{2}\) \(\mathrm{pK}_{\mathrm{a}}=\mathrm{pK}_{\mathrm{b}}\) \(\Rightarrow \mathrm{pH}=\frac{\mathrm{pK}_{\mathrm{W}}}{2}=7\)
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