JEE Mains · Chemistry · STD 12 - 9. Amines
Consider the following sequence of reactions:
11.25 mg of chlorobenzene will produce __________ \(\times 10^{-1} \mathrm{mg}\) of product B .
(Consider the reactions result in complete conversion.)
[Given molar mass of \(\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{N}\) and Cl as \(12,1,16,14\) and \(35.5 \mathrm{~g} \mathrm{~mol}^{-1}\) respectively]
- A 90
- B 93
- C 96
- D 99
Answer & Solution
Correct Answer
(B) 93
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{11.25 \times 10^{-3}}{112.5}=\frac{x \times 10^{-1} \times 10^{-3}}{93} \\ & x \times 10^{-1}=93 \times 0.1 \\ & x=93 \mathrm{mg}\end{aligned}\)
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