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JEE Mains · Physics · STD 12 -7. Alternating current

A transmitting station releases waves of wavelength \(960\, m\). A capacitor of \(2.56\, \mu F\) is used in the resonant circuit. The self inductance of coil necessary for resonance is ............. \(-\times 10^{-8} H\)

  1. A \(5\)
  2. B \(15\)
  3. C \(20\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(10\)

Step-by-step Solution

Detailed explanation

\(\lambda=960 m\) \(C =2.56 \mu F =2.56 \times 10^{-6} F\) \(c=3 \times 10^{8} m / s\) \(L =?\) Now at resonance, \(\omega_{0}=\frac{1}{\sqrt{L C}}\) [Resoant frequency] \(2 \pi f _{0}=\frac{1}{\sqrt{ LC }}\) On substituting \(f _{0}=\frac{ c }{\lambda},\) we have…
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