JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
Number of isomeric products formed by monochlorination of \(2\)-methylbutane in presence of sunlight is _______.
- A \(2\)
- B \(3\)
- C \(10\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
\(\therefore\) Number of isomeric products = \(6\)
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