JEE Mains · Chemistry · STD 11 - 2. structure of atom
In an atom, total number of electrons having quantum numbers \(\mathrm{n}=4,\left|\mathrm{~m}_{\mathrm{l}}\right|=1\) and \(\mathrm{m}_{\mathrm{s}}=-\frac{1}{2}\) is _______.
- A \(4\)
- B \(7\)
- C \(8\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}=4\) l \(\quad \mathrm{m}_{\ell}\) \(0 \quad 0\) \(1-1,0,+1\) \(2-2,-1,0,+1,+2,+3\) So number of orbital associated with \(\mathrm{n}=4,\left|\mathrm{~m}_{\mathrm{l}}\right|=1\) are \(6\) Now each orbital contain one \(e^{-}\)with \(\mathrm{m}_x=-\frac{1}{2}\)
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