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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2023
  • Medium
  • Numerical

\(64\) identical drops each charged upto potential of \(10\,mV\) are combined to form a bigger dorp. The potential of the bigger drop will be \(..........\,mV\)

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Answer & Solution

Correct Answer

(D) \(160\)

Step-by-step Solution

Detailed explanation

Let \(q =\) charge on each drop

\(V =\frac{ Kq }{ r } \text {-.- (1) }\)

Now for combination of 64 drop

\(64 \times \frac{4}{3} \pi r^3=\frac{4}{3} \pi R^3\)

\(R=4 r\)

And \(Q =64 q\)

Potential of bigger drop

\(=\frac{ KQ }{ R }=\frac{ K 64 q }{4 r }=16 \frac{ Kq }{ r }\)

\(=16 \times 10\,mV =160\,mV\)

Correct answer is \(160 .\)

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