JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
If the half life of a first order reaction is \(6.93\) minutes then the time required for completion of \(99\)% of the reaction will be _____ minutes.
(Given : \(\log 2 = 0.3010\))
- A 46.01
- B 46.02
- C 46.03
- D 46.06
Answer & Solution
Correct Answer
(D) 46.06
Step-by-step Solution
Detailed explanation
For a first-order reaction, the rate constant \(k\) is given by: \(k = \dfrac{2.303 \log 2}{t_{1/2}}\) Using the standard approximation \(2.303 \log 2 \approx 0.693\): \(k = \dfrac{0.693}{6.93} = 0.1 \text{ min}^{-1}\) The time required for \(99\%\) completion of the reaction is…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Kjeldahl's method was used for the estimation of nitrogen in an organic compound. The ammonia evolved from \(0.55\, g\) of the compound neutralised \(12.5\, mL\) of \(1\, M \,H _{2} SO _{4}\) solution. The percentage of nitrogen in the compound is \(.....\) (Nearest integer)JEE Mains 2022 Easy
- Arrange the following in decreasing acidic strength.
JEE Mains 2022 Medium - The correct statements from the following are : \((A)\) The decreasing order of atomic radii of group \(13\) elements is \(\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}\). \((B)\) Down the group \(13\) electronegativity decreases from top to bottom. \((C)\) \(\mathrm{Al}\) dissolves in dil. \(\mathrm{HCl}\) and liberate \(\mathrm{H}_2\) but conc. \(\mathrm{HNO}_3\) renders Al passive by forming a protective oxide layer on the surface. \((D)\) All elements of group \(13\) exhibits highly stable +1 oxidation state. \((E)\) Hybridisation of \(\mathrm{Al}\) in \(\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}\) ion is \(\mathrm{sp}^3 \mathrm{~d}^2\). Choose the correct answer from the options given below:JEE Mains 2024 Medium
- \(\mathrm{KMnO}_4\) acts as an oxidising agent in acidic medium. ' X ' is the difference between the oxidation states of Mn in reactant and product. ' Y ' is the number of ' d ' electrons present in the brown red precipitate formed at the end of the acetate ion test with neutral ferric chloride. The value of \(\mathrm{X}+\mathrm{Y}\) is ______.JEE Mains 2025 Hard
- For the thermal decomposition of \(\mathrm{N}_2 \mathrm{O}_5(\mathrm{~g})\) at constant volume, the following table can be formed, for the reaction mentioned below.
\(2 \mathrm{~N}_2 \mathrm{O}_5(\mathrm{~g}) \rightarrow 2 \mathrm{~N}_2 \mathrm{O}_4(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g})\)
\(\mathrm{x}=\ldots \times 10^{-3} \mathrm{~atm} \text { [nearest integer] }\)
Given : Rate constant for the reaction is \(4.606 \times 10^{-2} \mathrm{~s}^{-1}\).JEE Mains 2025 Easy - Number of compounds from the following which will not dissolve in cold \(NaHCO _3\) and \(NaOH\) solutions but will dissolve in hot \(NaOH\) solution is \(........\).
JEE Mains 2023 Hard
More PYQs from JEE Mains
- A particle which is experiencing a force, given by \(\vec F = 3\vec i -12\vec j\), undergoes a displacement of \(\vec d = 4\vec i\) . If the particle had a kinetic energy of \(3\, J\) at the beginning of the displacement, what is its kinetic energy at the end of the displacement?JEE Mains 2019 Medium
- Two wires \(A\) and \(B\) made of different materials of length 6.0 cm and 5.4 cm, respectively and area of cross sections \(3.0 \times 10^{-5} m^2\) and \(4.5 \times 10^{-5} m^2\), respectively are stretched by the same magnitude under a given load. The ratio of the Young's modulus of \(A\) to that of \(B\) is \(x : 3\). The value of x is ___________.JEE Mains 2026 Easy
- Number of atoms in the following samples of substances is largest inJEE Mains 2013 Hard
- For the following Assertion and Reason, the correct option is Assertion \((A)\) \(:\) When Cu \((II)\) and sulphide ions are mixed, they react together extremely quickly to give a solid. Reason \((R)\) \(:\) The equilibrium constant of \(Cu ^{2+}( aq )+ S ^{2-}( aq ) \rightleftharpoons \operatorname{CuS}( s )\) is high because the solubility product is low.JEE Mains 2020 Medium
- Young's moduli of the material of wires \(A\) and \(B\) are in the ratio of \(1: 4\), while its area of cross sections are in the ratio of \(1: 3\). If the same amount of load is applied to both the wires, the amount of elongation produced in the wires \(A\) and \(B\) will be in the ratio of [Assume length of wires \(A\) and \(B\) are same]JEE Mains 2023 Medium
- Let \(p\) and \(p+2\) be prime numbers and let \(\Delta=\left|\begin{array}{ccc}p ! & (p+1) ! & (p+2) ! \\ (p+1) ! & (p+2) ! & (p+3) ! \\ (p+2) ! & (p+3) ! & (p+4) !\end{array}\right|\) Then the sum of the maximum values of \(\alpha\) and \(\beta\), such that \(p ^{\alpha}\) and \(( p +2)^{\beta}\) divide \(\Delta\), is \(........\)JEE Mains 2022 Hard