JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A sample of a hydrate of barium chloride weighing \(61\,g\) was heated until all the water of hydration is removed. The dried sample weight is \(52\,g.\) The formula of the hydrated salt is : ( atomic mass, \(Ba = 137\,amu,\,\,Cl = 35.5\,amu\) )
- A \(BaC{l_2}.4{H_2}O\)
- B \(BaC{l_2}.3{H_2}O\)
- C \(BaC{l_2}.{H_2}O\)
- D \(BaC{l_2}.2{H_2}O\)
Answer & Solution
Correct Answer
(D) \(BaC{l_2}.2{H_2}O\)
Step-by-step Solution
Detailed explanation
Weight of hydrated \(BaCl_2 = 61\,g\) Weight of anhydrous \(BaCl_2 = 52\,g\) Loss in mass \(= 9\,g\) Assuming \(BaCl_2.xH_2O\) as hydrate mass of \(H_2O = 9\,g\) Moles of \({{H}_{2}}O=\frac{9}{18}=0.5\) Grass molecular let of \(BaCl_2 = 208\) \(\%\) of \(H_2O\) in this hydrated…
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