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JEE Mains · Chemistry · STD 11 - 2. structure of atom

If the de Brogile wavelength of the electron in \(n^{th}\) Bohr orbit in a hydrogenic atom is equal to \(1.5\,\pi a_0\) ( \(a_0\) is Bohr radius), then the value of \(n/z\) is

  1. A \(0.40\)
  2. B \(1.50\)
  3. C \(1.0\)
  4. D \(0.75\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.75\)

Step-by-step Solution

Detailed explanation

\(2\pi r = n\lambda \) \(\lambda = \frac{{2\pi r}}{n} = \frac{{2\pi {n^2}{a_0}}}{{n \times Z}} = 2\pi \frac{n}{Z}{a_0}\) \(\lambda = 1.5\pi {a_0}\) \(\therefore \,2\pi \frac{n}{Z}{a_0} = 1.5\pi {a_0}\) \(\therefore \frac{n}{Z} = \frac{{1.5}}{2} = 0.75\)
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