JEE Mains · Chemistry · STD 12 - 7. Alcohol, phenol and ethers
Given below are two statement : Statement \(I\) : Bromination of phenol in solvent with low polarity such as \(\mathrm{CHCl}_3\) or \(\mathrm{CS}_2\) requires Lewis acid catalyst. Statement \(II\) : The lewis acid catalyst polarises the bromine to generate \(\mathrm{Br}^{+}\). In the light of the above statements, choose the correct answer from the options given below :
- A Statement \(I\) is true but Statement \(II\) is false.
- B Both Statement \(I\) and Statement \(II\) are true
- C Both Statement \(I\) and Statement \(II\) are false.
- D Statement \(I\) is false but Statement \(II\) is true.
Answer & Solution
Correct Answer
(D) Statement \(I\) is false but Statement \(II\) is true.
Step-by-step Solution
Detailed explanation
Phenol is a highly activated compound which can undergo bromination directly with Bromine without any lewis acid.
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