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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

For the reaction \(H _{2} F _{2( g )} \rightarrow H _{2( g )}+ F _{2( g )}\) \(\Delta U =-59.6\,kJ\,mol ^{-1} \text { at } 27^{\circ}\,C\). The enthalpy change for the above reaction is (-) \(kJ mol ^{-1}\) [nearest integer] Given : \(R =8.314\,JK ^{-1}\,mol ^{-1}\)

  1. A \(57\)
  2. B \(55\)
  3. C \(56\)
  4. D \(54\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(57\)

Step-by-step Solution

Detailed explanation

\(\Delta H =\Delta U +\Delta n _{ g } RT\) \(\Delta H =-59.6+1 \times 8.314 \times 300 \times 10^{-3}=-57.10\)
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