JEE Mains · Physics · STD 12 - 13. Nuclei
A sample contains \(10^{-2}\, kg\) each of two substances A and \(B\) with half lives \(4 \,s\) and \(8 \,s\) respectively. The ratio of then atomic weights is \(1: 2\) The ratio of the amounts of \(A\) and \(B\) after \(16 \,s\) is \(\frac{x}{100}\). the value of \(x\) is........
- A \(55\)
- B \(50\)
- C \(90\)
- D \(150\)
Answer & Solution
Correct Answer
(B) \(50\)
Step-by-step Solution
Detailed explanation
\(N_{t}=N_{0}(0.5)^{\frac{t}{t_{1 / 2}}}\) \(=\frac{ m }{ M } \times N _{ A }(0.5)^{\frac{ t }{ t _{/ 2}}}\) \(\frac{N_{1}}{N_{2}}=\frac{M_{2}}{M_{1}}(0.5)^{t}\left[\frac{1}{T_{ A }}-\frac{1}{T_{B}}\right]\)…
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