JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2022
- Medium
- Numerical
A sample contains \(10^{-2}\, kg\) each of two substances A and \(B\) with half lives \(4 \,s\) and \(8 \,s\) respectively. The ratio of then atomic weights is \(1: 2\) The ratio of the amounts of \(A\) and \(B\) after \(16 \,s\) is \(\frac{x}{100}\). the value of \(x\) is........
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(50\)
Step-by-step Solution
Detailed explanation
\(N_{t}=N_{0}(0.5)^{\frac{t}{t_{1 / 2}}}\)
\(=\frac{ m }{ M } \times N _{ A }(0.5)^{\frac{ t }{ t _{/ 2}}}\)
\(\frac{N_{1}}{N_{2}}=\frac{M_{2}}{M_{1}}(0.5)^{t}\left[\frac{1}{T_{ A }}-\frac{1}{T_{B}}\right]\)
\(=2(0.5)^{16 \times \frac{1}{8}}=\frac{2}{4}=\frac{1}{2}=\frac{ x }{100}\)
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