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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2022
  • Medium
  • Numerical

A sample contains \(10^{-2}\, kg\) each of two substances A and \(B\) with half lives \(4 \,s\) and \(8 \,s\) respectively. The ratio of then atomic weights is \(1: 2\) The ratio of the amounts of \(A\) and \(B\) after \(16 \,s\) is \(\frac{x}{100}\). the value of \(x\) is........

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Answer & Solution

Correct Answer

(B) \(50\)

Step-by-step Solution

Detailed explanation

\(N_{t}=N_{0}(0.5)^{\frac{t}{t_{1 / 2}}}\)

\(=\frac{ m }{ M } \times N _{ A }(0.5)^{\frac{ t }{ t _{/ 2}}}\)

\(\frac{N_{1}}{N_{2}}=\frac{M_{2}}{M_{1}}(0.5)^{t}\left[\frac{1}{T_{ A }}-\frac{1}{T_{B}}\right]\)

\(=2(0.5)^{16 \times \frac{1}{8}}=\frac{2}{4}=\frac{1}{2}=\frac{ x }{100}\)

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