JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Match List \(I\) with List \(II\) :-
| सूची-\(I\) coordination compounds | सूची-\(II\) numbar of unpaired electrons |
| \(A\) \(\left[ Cr ( CN )_6\right]^{3-}\) | \(I\) \(0\) |
| \(B\) \(\left[ Fe \left( H _2 O \right)_6\right]^{2+}\) | \(II\) \(3\) |
| \(C\) \(\left[ Co \left( NH _3\right)_6\right]^{3+}\) | \(III\) \(2\) |
| \(D\) \(\left[ Ni \left( NH _3\right)_6\right]^{2+}\) | \(IV\) \(4\) |
- A A - II, B - IV, C - I, D - III
- B A - IV, B-III, C - II, D - I
- C A - III, B - IV, C - I, D - II
- D A - II , B - I , C - IV , D - III
Answer & Solution
Correct Answer
(A) A - II, B - IV, C - I, D - III
Step-by-step Solution
Detailed explanation
For option \((A)\) \(Cr ^{+3}: 3 d ^3\) \(CN ^{-} \rightarrow SFL\) \(\Rightarrow \text { No. of unpaired electrons }=3\) For option \((B)\) \(Fe ^{+2}: 3 d ^6\) \(H _2 O : WFL\) No. of unpaired electrons \(=4\) For option \((C)\) \(Co ^{+3}: 3 d ^6\) \(NH _3: SFL\) No. of…
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