JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
For the given hypothetical reactions, the equilibrium constants are as follows: \(\mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0\) \(\mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0\) \(\mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0\) The equilibrium constant for the reaction \(\mathrm{X} \rightleftharpoons \mathrm{W}\) is _______.
- A \(6.0\)
- B \(12.0\)
- C \(8.0\)
- D \(7.0\)
Answer & Solution
Correct Answer
(C) \(8.0\)
Step-by-step Solution
Detailed explanation
\(\mathrm{X} \rightleftharpoons \mathrm{Y} \mathrm{k}_1=1\) \(\mathrm{Y} \rightleftharpoons \mathrm{Z} \mathrm{k}_2=2\) \(\mathrm{Z} \rightleftharpoons \omega \mathrm{k}_3=4\) \(\mathrm{X} \rightleftharpoons \omega \mathrm{k}_1 \cdot \mathrm{k}_2 \cdot \mathrm{k}_3\)…
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