JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
The reaction of propene with \(HOCl (Cl_2 + H_2O)\) proceeds through the intermediate :
- A \(CH_3 -CH(OH)-CH_2^+\)
- B \(CH_3 -CHCl-CH_2^+\)
- C \(CH_3 -CH^+ -CH_2 -OH\)
- D \(CH_3 -CH^+ -CH_2 -Cl\)
Answer & Solution
Correct Answer
(D) \(CH_3 -CH^+ -CH_2 -Cl\)
Step-by-step Solution
Detailed explanation
\(C{{H}_{3}}-CH=C{{H}_{2}}\xrightarrow[(electrophilic\,addition)]{\overset{\delta -}{\mathop{HO}}\,-\overset{\delta +}{\mathop{Cl}}\,}\) \(\underset{(\operatorname{int}ermediate)}{\mathop{C{{H}_{3}}-\overset{+}{\mathop{C}}\,H-C{{H}_{2}}-Cl}}\,\)…
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