JEE Mains · Chemistry · STD 11 - 2. structure of atom
Excited hydrogen atom emits light in the ultraviolet region at \(2.47 \times 10^{15}\,Hz.\) With this frequency, the energy of a single photon is \((h = 6.63 \times 10^{-34}\,Js)\)
- A \(8.041 \times 10^{-40}\,J\)
- B \(2.680 \times 10^{-19}\,J\)
- C \(1.640 \times 10^{-18}\,J\)
- D \(6.111 \times 10^{-17}\,J\)
Answer & Solution
Correct Answer
(C) \(1.640 \times 10^{-18}\,J\)
Step-by-step Solution
Detailed explanation
\(E = hv\) \(= 6.63 \times 10^{-34} \times 2.47 \times 10^{15}\) \(= 1 .640 \times 10^{-18}\,J\)
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