ExamBro
ExamBro
JEE Mains · Chemistry · STD 11 - 2. structure of atom

The wave function \((\Psi)\) of \(2 s\) is given by \(\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{ r }{ a _0}\right) e ^{- r / 2 a _0}\) At \(r=r_0\), radial node is formed. Thus, \(r_0\) in terms of \(a_0\)

  1. A \(r_0=a_0\)
  2. B \(r_0=4 a_0\)
  3. C \(r _0=\frac{ a _0}{2}\)
  4. D \(r_0=2 a_0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(r_0=2 a_0\)

Step-by-step Solution

Detailed explanation

At node \(\Psi_{2 s }=0\) \(\therefore 2-\frac{ r _0}{ a _0}=0\) \(\therefore r _0=2 a _0\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app