JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Elevation in boiling point for \(1.5\) molal solution of glucose in water is \(4 \,K\). The depression in freezing point for \(4.5\) molal solution of glucose in water is \(4\, K\) The ratio of molal elevation constant to molal depression constant \(\left( K _{ b } / K _{ f }\right)\) is \(....\)
- A \(4\)
- B \(1\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\(\Delta T _{ b }= i\,K _{ b } \,m\) \(\Delta T _{ f }= i\,K _{ i } \,m\) \(\frac{4}{4}=\frac{ K _{ b } 1.5}{ K _{ f } 4.5}\) \(\frac{ K _{ b }}{ K _{ f }}=3\)
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