JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
At the sea level, the dry air mass percentage composition is given as nitrogen gas : 70.0, oxygen gas : 27.0 and argon gas : 3.0. If total pressure is 1.15 atm , then calculate the ratio of followings respectively :
(i) partial pressure of nitrogen gas to partial pressure of oxygen gas
(ii) partial pressure of oxygen gas to partial pressure of argon gas
(Given : Molar mass of \(\mathrm{N}, \mathrm{O}\) and Ar are 14, 16, and \(40 \mathrm{~g} \mathrm{~mol}^{-1}\) respectively)
- A \(4.26,19.3\)
- B \(2.59,11.85\)
- C \(5.46,17.8\)
- D \(2.96,11.2\)
Answer & Solution
Correct Answer
(D) \(2.96,11.2\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{P}_{\mathrm{N}_2}}{\mathrm{Po}_2}=\frac{\mathrm{x}_{\mathrm{N}_2} \cdot \mathrm{P}_{\mathrm{T}}}{\mathrm{x}_{\mathrm{O}_2} \cdot \mathrm{P}_{\mathrm{T}}}=\frac{\mathrm{n}_{\mathrm{N}_2}}{\mathrm{n}_{\mathrm{O}_2}}\) {using Dalton's law of partial pressure}…
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