JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and \( PQ_{2} \). When 1 g of PQ is dissolved in 50 g of solvent 'A', \( \Delta T_{b} \) was 1.176 K while when 1 g of \( PQ_{2} \) is dissolved in 50 g of solvent 'A', \( \Delta T_{b} \) was 0.689 K. \( K_{b} \) of 'A' = \( 5 \, K \, kg \, mol^{-1} \). The molar masses of elements P and Q (in \( g \, mol^{-1} \)) respectively, are:
- A 70, 110
- B 65, 145
- C 60, 25
- D 25, 60
Answer & Solution
Correct Answer
(D) 25, 60
Step-by-step Solution
Detailed explanation
\( (\Delta T_{b})_{PQ} = K_{b}m \) \( 1.176 = 5 \times \frac{1}{M_{1}} \times \frac{1000}{50} \) \( M_{1} = 85.03 \) \( (\Delta T_{b})_{PQ_{2}} = 5 \times \frac{1}{M_{2}} \times \frac{1000}{50} = 0.689 \) \( M_{2} = 145.13 \) Let molar mass of \(P \& Q\) are \(M_P\) and \(M_Q\)…
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