JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Consider the following aqueous solutions.
I. 2.2 g Glucose in 125 mL of solution.
II. 1.9 g Calcium chloride in 250 mL of solution.
III. 9.0 g Urea in 500 mL of solution.
IV. 20.5 g Aluminium sulphate in 750 mL of solution.
The correct increasing order of boiling point of these solutions will be:
[Given: Molar mass in \(g mol^{-1}\): \(H=1, C=12, N=14, O=16, Cl=35.5, Ca=40, Al=27, S=32\)]
- A I < II < III < IV
- B III < II < I < IV
- C II < III < IV < I
- D II < III < I < IV
Answer & Solution
Correct Answer
(A) I < II < III < IV
Step-by-step Solution
Detailed explanation
\(\Delta T_{b} = i \cdot k_{b} \cdot m\) For dilute solution ( \(M=m\) )Molarity \(i \times m\) (I) \(M _{\text {glucose }}=\frac{2.2}{180} \times \frac{1000}{125}=0.098\) \(0.098 \times 1\) (II) \(M _{ CaCl _2}=\frac{1.9}{111} \times \frac{1000}{250}=0.068\) \(0.068 \times 3\)…
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