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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Electrode potentials \((E^o)\) are given below \(Cu^+ /Cu = + 0.52\, V\), \(Fe^{3+} /Fe^{2+} = +0.7 7\, V\), \(\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, = + 0.54\,V,\) \(Ag^+ /Ag = + 0.88\,V\). Based on the above potentials, strongest oxidizing agent will be
- A \(Cu^+\)
- B \(Fe^{3+}\)
- C \(Ag^+\)
- D \(I_2\)
Answer & Solution
Correct Answer
(C) \(Ag^+\)
Step-by-step Solution
Detailed explanation
Higher the value of reduction potential stronger will be the oxidising hence based on the given values \(Ag^+\) will be strongest oxidizing agent
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