ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

\(A\) and \(B\) decompose via first order kinetics with half-lives \(54.0\, min\) and \(18.0\, min\) respectively. Starting from an equimolar non reactive mixture of \(A\) and \(B\), the time taken for the concentration of \(A\) to become \(16\) times that of \(B\) is ...... \(min.\) (Round off to the Nearest Integer).

  1. A \(110\)
  2. B \(108\)
  3. C \(208\)
  4. D \(136\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(108\)

Step-by-step Solution

Detailed explanation

Given \(t _{2}=54\, min \quad T _{1 / 2}=18 \,min\) \(A\) \(\quad\) \(B\) \(\Rightarrow \quad\) To calculate \(:\left[ A _{t}\right]=16 \times\left[ B _{ t }\right] \ldots .(1)\) time \(=?\) \(\Rightarrow \quad\) For \(I\) order kinetic :…