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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
A solution of copper sulphate \((CuSO_4)\) is electrolysed for \(10\, minutes\) with a current of \(1.5\, amperes\). The mass of copper deposited at the cathode (at . mass of \(Cu = 63\,u\)) is ............ \(\mathrm{g}\)
- A \(0.3892\)
- B \(0.2938\)
- C \(0.2398\)
- D \(0.3928\)
Answer & Solution
Correct Answer
(B) \(0.2938\)
Step-by-step Solution
Detailed explanation
\(W=Zit\) where \(Z\,=\) Electrochemical equivalent Eq. wt. of copper \(=\,\frac {63}{2}=31.5\) \(Z\,=\,\frac {31.5}{96500}\) \(W\, = \,Zit\, = \,\frac{{31.5}}{{96500}}\, \times \,1.5\, \times 10 \times 60\, = \,0.2938\,g\)
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