JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Consider the given data :
(a) \(\mathrm{HCl}(\mathrm{g})+10 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{HCl}.10 \mathrm{H}_2 \mathrm{O}\)
\(\Delta \mathrm{H}=-69.01 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
(b) \(\mathrm{HCl}(\mathrm{g})+40 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{HCl}.40 \mathrm{H}_2 \mathrm{O}\)
\(\Delta \mathrm{H}=-72.79 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Choose the correct statement :
- A Dissolution of gas in water is an endothermic process
- B The heat of solution depends on the amount of solvent.
- C The heat of dilution for the \(\mathrm{HCl}\left(\mathrm{HCl} \cdot 10 \mathrm{H}_2 \mathrm{O}\right.\) to \(\left.\mathrm{HCl}.40 \mathrm{H}_2 \mathrm{O}\right)\) is \(3.78 \mathrm{~kJ} \mathrm{~mol}^{-1}\).
- D The heat of formation of HCl solution is represented by both (a) and (b)
Answer & Solution
Correct Answer
(B) The heat of solution depends on the amount of solvent.
Step-by-step Solution
Detailed explanation
From the given information \(\Delta \mathrm{H}\) is negative so it means dissolution of gas \(\mathrm{HCl}(\mathrm{g})\) is exothermic. \(\mathrm{HCl}(\mathrm{g})+10 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{HCl}.10 \mathrm{H}_2 \mathrm{O}\) ...(1)…
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