JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
Which one of the following alkenes when treated with \(HCl\) yields majorly an anti Markovnikov product?
- A \(H_2N -CH = CH_2\)
- B \(F_3C -CH = CH_2\)
- C \(CH_3 O -CH = CH_2\)
- D \(Cl -CH = CH_2\)
Answer & Solution
Correct Answer
(B) \(F_3C -CH = CH_2\)
Step-by-step Solution
Detailed explanation
In this case antimarkonikov product will be formed as major product because carbocation formed at a double bonded carbon having lesser number of \(H\) atom will be unstable due to presence of an electron with drawing group \((CF_3)\) attached to it.
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