JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
Consider the above reaction where \(6.1 \,g\) of benzoic acid is used to get \(7.8\, g\) of \(m\) -bromo benzoic acid. The percentage yield of the product is ....... . (Round off to the Nearest integer) [Given : Atomic masses : \(C =12.0 \,u , H : 1.0\, u,O : 16.0 \,u , Br =80.0 \,u ]\)
- A \(78\)
- B \(70\)
- C \(78\)
- D \(52\)
Answer & Solution
Correct Answer
(C) \(78\)
Step-by-step Solution
Detailed explanation
Moles of Benzoic acid \(=\frac{6.1}{122}\) \(=\) moles of m-bromobenzoic acid So, weight of m-bromobenzoic acid \(=\frac{6.1}{122} \times 201\, gm\) \(=10.05\, gm\) \(\%\) yield \(=\frac{\text { Actual weight }}{\text { Theoretical weight }} \times 100\)…
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